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1/2x^2-7=74
We move all terms to the left:
1/2x^2-7-(74)=0
Domain of the equation: 2x^2!=0We add all the numbers together, and all the variables
x^2!=0/2
x^2!=√0
x!=0
x∈R
1/2x^2-81=0
We multiply all the terms by the denominator
-81*2x^2+1=0
Wy multiply elements
-162x^2+1=0
a = -162; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-162)·1
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{2}}{2*-162}=\frac{0-18\sqrt{2}}{-324} =-\frac{18\sqrt{2}}{-324} =-\frac{\sqrt{2}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{2}}{2*-162}=\frac{0+18\sqrt{2}}{-324} =\frac{18\sqrt{2}}{-324} =\frac{\sqrt{2}}{-18} $
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